产品详情资料
电压打印在每列的开头。所有模块都使用5VDC电源,相对较少的模块也使用两个24VDC电源中的一个或两个。对于给定的模块,通过将电流值(以安培为单位)乘以该列的电压,计算表中包含电流值的每列的功耗。对于使用多个电压的模块,将计算的功率值相加,得出模块的总功率。示例1:“负载要求”表显示IC693CPU352模块从+5VDC电源汲取:910 mA。两个12VDC电源F F-2系列90–30 PLC I/O模块规格–2000年7月GFK–0898F中的任何一个都没有电流。要计算功耗,请将0.910安培乘以5伏特。答案是:4.55瓦(该模块耗散的热量)示例2:“负载要求”表显示IC693MDL241模块从+5VDC电源汲取80 mA从+24V DC隔离电源汲取125 mA计算+5VDC电源的功耗:将0.08安培乘以5伏特得出0.40瓦的值。要计算+24V DC电源的功耗:将0.125安培乘以24伏特,得出3.0瓦特的值。将两者相加,我们发现该模块的总散热量为3.4瓦。第2步:PLC电源的计算90系列电源的基本规则是其效率为66%。说明这一点的另一种方式是,电源每向PLC输送2瓦功率,就会以热量的形式消耗1瓦功率。因此,您可以使用上述步骤1中的方法计算特定电源所服务的机架中所有模块的总功率需求,然后将该数字除以2,得出电源消耗值。
The voltage is printed at the head of each column. All modules use the 5VDC supply, and a relatively few modules also use one or both of the two 24VDC supplies.For a given module, calculate the power dissipation for each column in the table that contains a current value by multiplying the current value (in Amps) times the voltage for that column. For modules using more than one voltage, add the calculated power values to arrive at the total for the module. Example 1: The “Load Requirements” table shows that the IC693CPU352 module draws:910 mA from the +5VDC supply.No current from either of the two 12VDC supplies F F-2 Series 90–30 PLC I/O Module Specifications – July 2000 GFK–0898F To calculate power dissipation, multiply 0.910 Amps times 5 Volts. The answer is: 4.55 Watts (of heat dissipated by this module) Example 2: The “Load Requirements” table shows that the IC693MDL241 module draws:80 mA from the +5VDC supply125 mA from the +24VDC Isolated supply To calculate power dissipation from the +5VDC supply: Multiply 0.08 Amps times 5 Volts to arrive at a value of 0.40 Watts. To calculate power dissipation from the +24VDC supply: Multiply 0.125 Amps times 24 Volts to arrive at a value of 3.0 Watts. Adding the two together, we find the total heat dissipated by this module is 3.4 Watts. Step 2: Calculation for PLC Power Supplies A basic rule for Series 90 power supplies is that they are 66% efficient. Another way of stating this is that the power supply dissipates 1 Watt of power in the form of heat for every 2 Watts of power it delivers to the PLC. Therefore, you can calculate the total power requirement for all of the modules in the rack served by a particular power supply using the method in Step 1 above, then divide that figure by 2 to arrive at the power supply dissipation value.
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主营产品简介
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●使用前:
在操作和维护,安装设备之前,请阅读并严格遵守安全相关的信息。
Read and strictly follow safety-related information before operatingmaintainingand installing equipment.
●使用者要求:
必须从事安装,组装或维护设备等相关工控电气机械以及其他相关技术的人员。
Must be engaged in the installation,assembly or maintenance of equipment and other related industriacontroeectrica machinery and other related technica personne.应用范围:
应用于品牌本系列工业以及生产生活自动化设备产品。
Used in the brand of this series of industriaand production automation eauipment products
适用于场景:系统集成,非标定制,产线升级改造,原设备电气替换等等。
Suitable for scenarios:system integration,non-standard customizationproduction line upgrading and transformation,electrical replacement of original equipment,etc.
●操作人员:
应该由本品牌专业培训操作员来安装、操作和维修设备。专业人员具有技术能力强,熟悉安全信息和安全实施:
熟悉设备的安装加工、操作和维护:熟悉处理所有的潜在危险情况。
Equipment should be installed,operated and maintained by trained operators from the brand
●危险情况
警告
.请注意使用人员的人身安全。
●除了产品特性以及功能,还需了解产品的使用寿命环境。
●充分学习产品使用手册,否则非专业人员可能会造成人身危险。
Study the product instruction manual thoroughlyotherwise it may cause personal danger to non-professionals.
●服务行业
适用水泥,木业,石业,橡胶,石油,化工,发电,环保,水处理,制冷,交通,钢铁,食品,饮料,船舶,制冷等行业
Applicable to cementwood,stone,rubber,petroleumchemical, power generation,
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